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A student incorrectly claims that (a−b)2=a2−b2(a - b)^2 = a^2 - b^2. To test this misconception, let a=2x+3a = 2x + 3 and b=2x−3b = 2x - 3. Calculate the exact algebraic difference between the student's incorrect formula (a2−b2)(a^2 - b^2) and the correct expanded formula (a−b)2(a - b)^2, expressing the result in terms of xx.

Answer and steps

Final answer

24x - 36

Steps

01

Find the value of a−ba - b and a+ba + b

To find the algebraic difference between the incorrect expression (a2−b2)(a^2 - b^2) and the correct expanded expression (a−b)2(a - b)^2, we can simplify each expression first using special product formulas.

Given: a=2x+3a = 2x + 3 b=2x−3b = 2x - 3

Calculate the sum and difference of aa and bb: a−b=(2x+3)−(2x−3)=2x+3−2x+3=6a - b = (2x + 3) - (2x - 3) = 2x + 3 - 2x + 3 = 6 a+b=(2x+3)+(2x−3)=4xa + b = (2x + 3) + (2x - 3) = 4x


02

Evaluate the incorrect formula (a2−b2)(a^2 - b^2)

Using the difference of squares pattern, a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b): a2−b2=(6)(4x)=24xa^2 - b^2 = (6)(4x) = 24x


03

Evaluate the correct formula (a−b)2(a - b)^2

Using the square of a binomial pattern, or directly substituting the evaluated difference (a−b)=6(a - b) = 6: (a−b)2=62=36(a - b)^2 = 6^2 = 36

(Note: Expanding algebraically yields a2−2ab+b2a^2 - 2ab + b^2, which also simplifies to 3636. A common pitfall is the "freshman's dream" error, where students distribute the exponent across subtraction and drop the middle term −2ab-2ab.)


04

Calculate the difference between the two expressions

Subtract the correct formula from the incorrect formula: Difference=(a2−b2)−(a−b)2\text{Difference} = (a^2 - b^2) - (a - b)^2 Difference=24x−36\text{Difference} = 24x - 36

Alternatively, by direct algebraic expansion: (a2−b2)−(a−b)2=(a2−b2)−(a2−2ab+b2)=2ab−2b2=2b(a−b)(a^2 - b^2) - (a - b)^2 = (a^2 - b^2) - (a^2 - 2ab + b^2) = 2ab - 2b^2 = 2b(a - b) Substituting b=2x−3b = 2x - 3 and (a−b)=6(a - b) = 6: 2(2x−3)(6)=12(2x−3)=24x−362(2x - 3)(6) = 12(2x - 3) = 24x - 36

Educational illustration for this question

Typical errors

OverviewACEpath Teacher's Diagnosis

01 The student subtracts in reverse order, calculating the correct formula minus the incorrect formula instead of the incorrect minus the correct.

Sample Student Work

Reviewed by ACEpath Teacher
Step-by-Step Review
Walk Through It with Your Teacher
Partially correct
  1. Step 1

    a^2 - b^2 = (2x + 3)^2 - (2x - 3)^2 = 24x

  2. Step 2

    a - b = (2x + 3) - (2x - 3) = 6   ⟹  \implies (a - b)^2 = 6^2 = 36

  3. Step 3

    Difference\text{Difference} = (a - b)^2 - (a^2 - b^2)

    Correct

    Difference\text{Difference} = (a^2 - b^2) - (a - b)^2

    The problem asks for the difference between the incorrect formula (a2−b2)(a^2 - b^2) and the correct formula (a−b)2(a - b)^2, which translates mathematically to (a2−b2)−(a−b)2(a^2 - b^2) - (a - b)^2, not (a−b)2−(a2−b2)(a - b)^2 - (a^2 - b^2).

  4. Step 4

    Difference=36−24x\text{Difference} = 36 - 24x

    Correct

    Difference=24x−36\text{Difference} = 24x - 36

    Due to setting up the subtraction in reverse order in the previous step, your final evaluated difference has the opposite sign.

WHAT YOU DID WELL
Compliments from Your Teacher

You correctly substituted the linear expressions for aa and bb into both formulas.

You skillfully simplified the difference of squares (2x+3)2−(2x−3)2(2x+3)^2 - (2x-3)^2 to obtain 24x24x.

You correctly determined that a−b=6a - b = 6 and squared it to find 3636.

THE ERROR
Where Your ACEpath Teacher Spotted the Mistake
Reversed Subtraction Order

You set up the difference as (correct)−(incorrect)(\text{correct}) - (\text{incorrect}) instead of (incorrect)−(correct)(\text{incorrect}) - (\text{correct}).

WHY IT HAPPENED
ACEpath Teacher's Diagnosis

In mathematical English, 'the difference between AA and BB' strictly specifies the order A−BA - B. Translating this phrase into subtraction requires preserving the exact order of the two named quantities.

REASONING PATH
Your ACEpath teacher’s suggested approach
Translate Order-Sensitive Phrases Carefully
  • The verbal phrase 'the difference between AA and BB' translates algebraically to A−BA - B.

  • Circle the first quantity as AA and the second quantity as BB, then write the subtraction skeleton (A)−(B)(A) - (B) before substituting their values.

CORRECTED PATH
ACEpath Teacher's Demonstration
  1. Identify the minuend and subtrahend from the question text: the first quantity is the incorrect formula (a2−b2)(a^2 - b^2), and the second quantity is the correct formula (a−b)2(a - b)^2.

  2. Write the difference expression in the specified order: Difference=(a2−b2)−(a−b)2\text{Difference} = (a^2 - b^2) - (a - b)^2.

  3. Substitute the simplified expressions into the formula: Difference=24x−36\text{Difference} = 24x - 36.

Final answer

24x - 36

NEXT STEPS
Final Takeaways from Your Teacher
  • Review key English subtraction phrases such as 'difference between AA and BB' (A−BA - B) versus 'subtract AA from BB' (B−AB - A).

  • Practice highlighting the two terms in word problems to avoid sign reversals in non-commutative operations.

OverviewACEpath Teacher's Diagnosis

02 The student fails to distribute the negative sign when expanding (2x + 3)² - (2x - 3)², leading to an incorrect result for a² - b².

Sample Student Work

Reviewed by ACEpath Teacher
Step-by-Step Review
Walk Through It with Your Teacher
Incorrect
  1. Step 1

    a^2 = (2x + 3)^2 = 4x^2 + 12x + 9   ⟹  \implies b^2 = (2x - 3)^2 = 4x^2 - 12x + 9

  2. Step 2

    a^2 - b^2 = 4x^2 + 12x + 9 - 4x^2 - 12x + 9 = 18

    Correct

    a^2 - b^2 = (4x^2 + 12x + 9) - (4x^2 - 12x + 9) = 24x

    When subtracting b2b^2, you did not enclose 4x2−12x+94x^2 - 12x + 9 in parentheses. Consequently, the negative sign was applied only to the first term rather than distributed to −12x-12x and +9+9.

  3. Step 3

    (a - b)^2 = (2x + 3 - 2x + 3)^2 = 6^2 = 36

  4. Step 4

    Difference\text{Difference} = 18 - 36 = -18

    Correct

    Difference=24x−36\text{Difference} = 24x - 36

    Your final subtraction structure was set up properly, but it inherited the incorrect value 1818 from Step 2 instead of 24x24x.

WHAT YOU DID WELL
Compliments from Your Teacher

You expanded both binomial squares (2x+3)2(2x + 3)^2 and (2x−3)2(2x - 3)^2 completely and accurately.

You correctly simplified a−ba - b by distributing the negative sign across (2x−3)(2x - 3) to arrive at 66.

You correctly squared the resulting constant to evaluate (a−b)2=36(a - b)^2 = 36.

THE ERROR
Where Your ACEpath Teacher Spotted the Mistake
Sign distribution error when subtracting polynomials

You forgot to keep parentheses around b2b^2 when writing a2−b2a^2 - b^2, which left the second and third terms with unchanged signs.

WHY IT HAPPENED
ACEpath Teacher's Diagnosis

Failing to treat a subtracted multi-term polynomial as a single grouped quantity requiring the distributive property: −(p+q+r)=−p−q−r-(p + q + r) = -p - q - r.

REASONING PATH
Your ACEpath teacher’s suggested approach
Enclose Subtracted Polynomials
  • Whenever you subtract an expression with two or more terms, always place parentheses around the entire expression: −(A−B+C)=−A+B−C-(A - B + C) = -A + B - C.

  • Write −(4x2−12x+9)-(4x^2 - 12x + 9) explicitly before combining terms.

Use Special Product Factorization as a Check
  • The difference of squares factors as a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b).

  • Notice that a−b=6a - b = 6 and a+b=4xa + b = 4x, giving a2−b2=(6)(4x)=24xa^2 - b^2 = (6)(4x) = 24x directly without full polynomial expansion.

CORRECTED PATH
ACEpath Teacher's Demonstration
  1. Substitute a2a^2 and b2b^2 with grouping parentheses: a2−b2=(4x2+12x+9)−(4x2−12x+9)a^2 - b^2 = (4x^2 + 12x + 9) - (4x^2 - 12x + 9).

  2. Distribute the negative sign across each term inside the second pair of parentheses: 4x2+12x+9−4x2+12x−94x^2 + 12x + 9 - 4x^2 + 12x - 9.

  3. Combine like terms: (4x2−4x2)+(12x+12x)+(9−9)=24x(4x^2 - 4x^2) + (12x + 12x) + (9 - 9) = 24x.

  4. Subtract (a−b)2=36(a - b)^2 = 36 from a2−b2=24xa^2 - b^2 = 24x: Difference=24x−36\text{Difference} = 24x - 36.

Final answer

24x - 36

NEXT STEPS
Final Takeaways from Your Teacher
  • Form the habit of writing grouping parentheses around any multi-term expression immediately after a minus sign.

  • Practice distributing negative signs across negative terms (such as −(−12x)=+12x-(-12x) = +12x) systematically before combining like terms.

  • Compare direct expansion with factoring patterns like (a−b)(a+b)(a - b)(a + b) to verify your algebraic calculations quickly.

OverviewACEpath Teacher's Diagnosis

03 The student forgets to square the difference when evaluating (a - b)², using a - b = 6 instead of 36.

Sample Student Work

Reviewed by ACEpath Teacher
Step-by-Step Review
Walk Through It with Your Teacher
Incorrect
  1. Step 1

    a^2 - b^2 = (4x^2 + 12x + 9) - (4x^2 - 12x + 9)   ⟹  \implies = 24x

  2. Step 2

    a - b = 2x + 3 - (2x - 3) = 6

  3. Step 3

    (a - b)^2 = 6

    Correct

    (a - b)^2 = 6^2 = 36

    You set (a−b)2(a - b)^2 equal to the value of a−ba - b itself (66) rather than squaring it to obtain 62=366^2 = 36.

  4. Step 4

    Difference=24x−6\text{Difference} = 24x - 6

    Correct

    Difference=24x−36\text{Difference} = 24x - 36

    Your subtraction step followed logically from your value in Step 3, but inherited the arithmetic mistake.

WHAT YOU DID WELL
Compliments from Your Teacher

You expanded both quadratic binomials accurately to get a2−b2=24xa^2 - b^2 = 24x.

You evaluated the difference of linear expressions a−ba - b correctly to get 66.

You set up the final difference expression using your evaluated values.

THE ERROR
Where Your ACEpath Teacher Spotted the Mistake
Omitted Exponent Operation

You wrote (a−b)2=6(a - b)^2 = 6 by directly copying the value of a−ba - b instead of computing 626^2.

WHY IT HAPPENED
ACEpath Teacher's Diagnosis

When substituting a pre-evaluated sub-expression into an outer power, you omitted the exponentiation step on the evaluated numeric value.

REASONING PATH
Your ACEpath teacher’s suggested approach
Substitute Inside the Power
  • If u=a−bu = a - b, then u2=(a−b)2u^2 = (a - b)^2. Always write (u)2(u)^2 before dropping parentheses.

  • Write (6)2(6)^2 explicitly on your paper before evaluating it as 3636.

CORRECTED PATH
ACEpath Teacher's Demonstration
  1. Substitute a−b=6a - b = 6 into (a−b)2(a - b)^2: (6)2=36(6)^2 = 36.

  2. Subtract the correct square from the difference of squares: (a2−b2)−(a−b)2=24x−36(a^2 - b^2) - (a - b)^2 = 24x - 36.

Final answer

24x - 36

NEXT STEPS
Final Takeaways from Your Teacher
  • Always write out parentheses with the exponent when substituting a simplified value into a power, such as (6)2(6)^2.

  • Verify edge values by expanding algebraically first: (a2−b2)−(a−b)2=2ab−2b2(a^2 - b^2) - (a - b)^2 = 2ab - 2b^2.

Lock it in

Similar question

01

Let u=3x+1u = 3x + 1 and v=3x−1v = 3x - 1. Calculate the exact algebraic difference between (u2−v2)(u^2 - v^2) and (u−v)2(u - v)^2 in terms of xx.

Answer

12x−412x - 4. First evaluate u2−v2=(3x+1)2−(3x−1)2=12xu^2 - v^2 = (3x+1)^2 - (3x-1)^2 = 12x. Next find u−v=2u - v = 2, so (u−v)2=4(u - v)^2 = 4. The difference between (u2−v2)(u^2 - v^2) and (u−v)2(u - v)^2 is (u2−v2)−(u−v)2=12x−4(u^2 - v^2) - (u - v)^2 = 12x - 4.

02

For two expressions M=5x+2M = 5x + 2 and N=5x−2N = 5x - 2, an erroneous identity claims (M−N)2=M2−N2(M - N)^2 = M^2 - N^2. Find the value of (M2−N2)−(M−N)2(M^2 - N^2) - (M - N)^2. Then, state the value if the order of subtraction is reversed.

Answer

40x−1640x - 16 for the direct difference, and 16−40x16 - 40x for the reversed order. We have M−N=4M - N = 4 and M+N=10xM + N = 10x. Thus M2−N2=(M−N)(M+N)=40xM^2 - N^2 = (M-N)(M+N) = 40x, and (M−N)2=42=16(M - N)^2 = 4^2 = 16. The forward difference is 40x−1640x - 16; reversing the subtraction gives 16−40x=−(40x−16)16 - 40x = -(40x - 16).

03

Let f(x)=(x+4)2−(x−4)2f(x) = (x + 4)^2 - (x - 4)^2 and g(x)=((x+4)−(x−4))2g(x) = ((x + 4) - (x - 4))^2. If the difference between f(x)f(x) and g(x)g(x) equals 3232, solve for xx.

Answer

x=6x = 6. Simplify f(x)=(x2+8x+16)−(x2−8x+16)=16xf(x) = (x^2 + 8x + 16) - (x^2 - 8x + 16) = 16x. Simplify g(x)=(8)2=64g(x) = (8)^2 = 64. The difference between f(x)f(x) and g(x)g(x) is f(x)−g(x)=16x−64f(x) - g(x) = 16x - 64. Setting 16x−64=3216x - 64 = 32 gives 16x=9616x = 96, so x=6x = 6.

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