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Solve the linear inequality −3(2x−5)≥4x−25-3(2x - 5) \ge 4x - 25 for xx, express the solution set in interval notation, and describe the geometric representation of the solution set on a real number line.

Answer and steps

Final answer

Interval notation: (−∞,4](-\infty, 4]; on the number line, a solid closed circle at x=4x = 4 with a shaded ray extending indefinitely to the left.

Steps

01

Expand and simplify both sides

To solve the inequality, write the solution in interval notation, and graph it on a number line, follow these steps:

Apply the distributive property to the left side of the inequality: −3(2x−5)≥4x−25-3(2x - 5) \ge 4x - 25 −6x+15≥4x−25-6x + 15 \ge 4x - 25

02

Collect variable terms and constant terms

Subtract 4x4x from both sides to group the xx-terms on the left: −6x−4x+15≥−25-6x - 4x + 15 \ge -25 −10x+15≥−25-10x + 15 \ge -25

Subtract 1515 from both sides to isolate the variable term: −10x≥−25−15-10x \ge -25 - 15 −10x≥−40-10x \ge -40

03

Divide by the coefficient of xx

Divide both sides by −10-10.

Important Rule: Whenever an inequality is multiplied or divided by a negative number, the direction of the inequality sign must be reversed.

−10x−10≤−40−10\frac{-10x}{-10} \le \frac{-40}{-10} x≤4x \le 4

04

Write in interval notation

The inequality x≤4x \le 4 includes all real numbers less than or equal to 44.

  • The lower bound extends indefinitely to the left: −∞-\infty (always written with an open parenthesis ().
  • The upper bound is 44, which is included in the solution set (written with a closed bracket ]).

Therefore, the interval notation is: (−∞,4](-\infty, 4]

05

Describe the graph on a number line

To represent x≤4x \le 4 geometrically on a horizontal number line:

  1. Place a solid (closed) circle at the point 44 to indicate that 44 is included in the solution set.
  2. Shade a continuous ray pointing to the left from 44, ending with an arrow pointing toward −∞-\infty, representing all values smaller than 44.
Educational illustration for this question

Typical errors

OverviewACEpath Teacher's Diagnosis

01 The student forgets to reverse the inequality direction when dividing by a negative number, resulting in x ≥ 4.

Sample Student Work

Reviewed by ACEpath Teacher
Step-by-Step Review
Walk Through It with Your Teacher
Incorrect
  1. Step 1

    -3(2x - 5) ≥\ge 4x - 25   ⟹  \implies -6x + 15 ≥\ge 4x - 25   ⟹  \implies -10x ≥\ge -40

  2. Step 2

    x≥4x \ge 4

    Correct

    x≤4x \le 4

    When dividing or multiplying both sides of an inequality by a negative number (here, −10-10), the inequality sign must flip direction. Dividing by −10-10 changes ≥\ge to ≤\le, yielding x≤4x \le 4.

  3. Step 3

    [4,∞)[4, \infty)](streamdown:incomplete-link)

    Correct

    (−∞,4](-\infty, 4]

    Your interval notation [4,∞)[4, \infty) correctly reflects your intermediate result x≥4x \ge 4, but because the sign was not reversed in the previous step, the true solution set is (−∞,4](-\infty, 4].

  4. Step 4

    A solid circle at \text{A solid circle at } 4  with shading extending to the right\text{ with shading extending to the right}

    Correct

    A solid circle at \text{A solid circle at } 4  with shading extending to the left toward \text{ with shading extending to the left toward } -∞\infty

    Your graph accurately matches your written interval [4,∞)[4, \infty), but since the actual solution is x≤4x \le 4, the ray should shade to the left toward −∞-\infty.](streamdown:incomplete-link)

WHAT YOU DID WELL
Compliments from Your Teacher

You expanded −3(2x−5)-3(2x - 5) accurately to get −6x+15-6x + 15.

You grouped variable terms and constant terms cleanly to isolate −10x≥−40-10x \ge -40.

You correctly used a solid closed circle at 44 to represent an inclusive endpoint.

THE ERROR
Where Your ACEpath Teacher Spotted the Mistake
Sign direction reversal omission

no

WHY IT HAPPENED
ACEpath Teacher's Diagnosis

You treated division by a negative coefficient just like division in an equation, overlooking the fundamental inequality rule that dividing or multiplying by a negative number reflects values across zero and reverses their relative order.

REASONING PATH
Your ACEpath teacher’s suggested approach
Check the divisor's sign
  • Whenever you multiply or divide an inequality by a negative quantity, the inequality symbol must immediately flip (e.g., ≥\ge becomes ≤\le).

  • Circle negative coefficients before dividing so you remember to flip the inequality sign in the very next line.

Test a test point
  • Any valid solution from your final set must satisfy the original inequality.

  • Pick an easy test point such as x=0x = 0. In the original inequality, −3(0−5)=15≥−25-3(0 - 5) = 15 \ge -25 is true, so 00 must be in the shaded region. Your graph shaded values greater than 44, leaving out 00, which signals an inverted sign.

CORRECTED PATH
ACEpath Teacher's Demonstration
  1. Divide both sides of −10x≥−40-10x \ge -40 by −10-10 and reverse the inequality symbol: x≤4x \le 4.

  2. Write x≤4x \le 4 in interval notation: (−∞,4](-\infty, 4].

  3. Plot on the number line: place a solid closed circle at 44 and shade the ray extending to the left toward −∞-\infty.

Final answer

Interval notation: (−∞,4](-\infty, 4]; Number line: a solid closed circle at 44 with a shaded ray extending to the left.

NEXT STEPS
Final Takeaways from Your Teacher
  • Practice solving 1-step inequalities involving negative division to build automaticity with sign reversal.

  • Form the habit of testing x=0x = 0 in the original problem to verify whether the shaded direction is correct.

OverviewACEpath Teacher's Diagnosis

02 The student incorrectly distributes the negative sign to the second term inside the parentheses as -15 instead of +15, leading to -10x ≥ -10 and x ≤ 1.

Sample Student Work

Reviewed by ACEpath Teacher
Step-by-Step Review
Walk Through It with Your Teacher
Partially correct
  1. Step 1

    -3(2x - 5) ≥\ge 4x - 25   ⟹  \implies -6x - 15 ≥\ge 4x - 25

    Correct

    -3(2x - 5) ≥\ge 4x - 25   ⟹  \implies -6x + 15 ≥\ge 4x - 25

    When distributing −3-3 to both terms inside the parentheses, multiplying two negative numbers gives a positive: (−3)×(−5)=+15(-3) \times (-5) = +15, not −15-15.

  2. Step 2

    -10x ≥\ge -10   ⟹  \implies x ≤\le 1

    Correct

    -10x ≥\ge -40   ⟹  \implies x ≤\le 4

    Your algebraic rearrangement and rule application were correct based on your previous step (including reversing the inequality symbol when dividing by −10-10), but the values were affected by the earlier sign mistake.

  3. Step 3

    (-∞\infty, 1]  and a solid dot at \text{ and a solid dot at } 1  shaded to the left\text{ shaded to the left}

    Correct

    (-∞\infty, 4]  and a solid dot at \text{ and a solid dot at } 4  shaded to the left\text{ shaded to the left}

    Your interval notation and number line representation accurately matched your value of x≤1x \le 1, but the correct endpoint is 44.

WHAT YOU DID WELL
Compliments from Your Teacher

You correctly remembered to reverse the direction of the inequality sign when dividing both sides by the negative coefficient −10-10.

You correctly represented a non-strict inequality (≤\le) using a closed bracket in interval notation and a solid circle on the number line.

You correctly shaded the number line toward negative infinity to represent values less than the endpoint.

THE ERROR
Where Your ACEpath Teacher Spotted the Mistake
Distributive Property Sign Error

Multiplying −3-3 by −5-5 yielded −15-15 instead of +15+15.

WHY IT HAPPENED
ACEpath Teacher's Diagnosis

Overlooking the interaction between the negative factor outside parentheses and the negative sign on the subtracted term inside parentheses.

REASONING PATH
Your ACEpath teacher’s suggested approach
Distribute Signs Carefully
  • For any real numbers aa, bb, and cc, −a(b−c)=−ab+ac-a(b - c) = -ab + ac.

  • Always circle or highlight the sign attached to each term inside the parentheses before distributing a negative multiplier.

CORRECTED PATH
ACEpath Teacher's Demonstration
  1. −3(2x)−3(−5)≥4x−25  ⟹  −6x+15≥4x−25-3(2x) - 3(-5) \ge 4x - 25 \implies -6x + 15 \ge 4x - 25

  2. Subtract 4x4x and 1515 from both sides: −10x≥−40-10x \ge -40

  3. Divide by −10-10 and flip the inequality sign: x≤4x \le 4

Final answer

Interval notation: (−∞,4](-\infty, 4]; on the number line, a solid closed circle at x=4x = 4 with a shaded ray extending to the left.

NEXT STEPS
Final Takeaways from Your Teacher
  • Review multiplying signed numbers, paying special attention to (−)(−)=(+)(-)(-) = (+).

  • Practice expanding parentheses where a negative constant multiplies a difference, such as −a(x−b)-a(x - b).

  • Substitute a test point (such as x=0x = 0) into the original inequality to check whether your final solution set satisfies it.

OverviewACEpath Teacher's Diagnosis

03 The student confuses non-strict and strict inequalities at the boundary, treating ≥ as > and using an open interval and an open circle at 4.

Sample Student Work

Reviewed by ACEpath Teacher
Step-by-Step Review
Walk Through It with Your Teacher
Partially correct
  1. Step 1

    −3(2x−5)≥4x−25  ⟹  −6x+15≥4x−25  ⟹  −10x≥−40-3(2x - 5) \ge 4x - 25 \implies -6x + 15 \ge 4x - 25 \implies -10x \ge -40

  2. Step 2

    x<4x < 4

    Correct

    x≤4x \le 4

    When dividing both sides of −10x≥−40-10x \ge -40 by −10-10, the inequality symbol reverses from ≥\ge to ≤\le. You correctly flipped the direction, but omitted the 'or equal to' bar, treating a non-strict inequality as a strict one.

  3. Step 3

    (−∞,4)(-\infty, 4)

    Correct

    (−∞,4](-\infty, 4]

    Because x≤4x \le 4 includes the boundary point 44, the upper bound requires a square bracket ] rather than a parenthesis ).

  4. Step 4

    An open circle at x=4x = 4 with a shaded ray extending to the left.

    Correct

    A solid (closed) circle at x=4x = 4 with a shaded ray extending indefinitely to the left.

    Because 44 is included in the solution set (x≤4x \le 4), the point at 44 must be plotted as a solid closed circle.

WHAT YOU DID WELL
Compliments from Your Teacher

You expanded −3(2x−5)-3(2x - 5) accurately using the distributive property.

You collected like terms correctly to reach −10x≥−40-10x \ge -40.

You correctly remembered to reverse the direction of the inequality when dividing by the negative coefficient −10-10.

THE ERROR
Where Your ACEpath Teacher Spotted the Mistake
Strict vs. Non-Strict Inequality Boundary Confusion

You wrote << instead of ≤\le when dividing both sides by −10-10.

WHY IT HAPPENED
ACEpath Teacher's Diagnosis

You focused on reversing the inequality direction upon dividing by a negative number, but lost track of whether the original inequality was strict or non-strict, unintentionally dropping the equality bar.

REASONING PATH
Your ACEpath teacher’s suggested approach
Preserve Equality Status
  • Dividing or multiplying by a negative number reverses the direction of the inequality, but does not alter whether equality is included: ≥\ge becomes ≤\le, and >> becomes <<.

  • Always copy the horizontal equality bar along with the flipped inequality sign unless you are intentionally splitting cases.

Match Symbols to Notation
  • Non-strict inequalities (≤,≥\le, \ge) always pair with square brackets [ or ] and solid closed circles on the number line.

  • Before writing interval notation or drawing a number line, inspect the inequality sign: if it has an equality bar, use a bracket and fill in the circle.

CORRECTED PATH
ACEpath Teacher's Demonstration
  1. Divide both sides by −10-10 and reverse ≥\ge to ≤\le: x≤4x \le 4.

  2. Express all values less than or equal to 44 in interval notation: (−∞,4](-\infty, 4].

  3. Graph the solution by plotting a solid closed circle at 44 and drawing a ray pointing left toward −∞-\infty.

Final answer

Interval notation: (−∞,4](-\infty, 4]; on the number line, a solid closed circle at x=4x = 4 with a shaded ray extending indefinitely to the left.

NEXT STEPS
Final Takeaways from Your Teacher
  • Review the correspondence table: ≤/≥⟷[ / ]⟷solid dot\le / \ge \longleftrightarrow [\ /\ ] \longleftrightarrow \text{solid dot}; </>⟷( / )⟷open dot< / > \longleftrightarrow (\ /\ ) \longleftrightarrow \text{open dot}.

  • Practice two-step inequalities where division by a negative coefficient occurs on a non-strict inequality to build the habit of keeping the equality bar intact.

Lock it in

Similar question

01

Solve the inequality −4x+7≤27-4x + 7 \le 27, express the solution in interval notation, and state the direction of the shaded ray on a number line.

Answer

Subtract 77: −4x≤20-4x \le 20. Divide by −4-4 and reverse the sign: x≥−5x \ge -5. Interval notation: [−5,∞)[-5, \infty). Shaded ray: starts with a solid closed circle at −5-5 and extends to the right.](streamdown:incomplete-link)

02

Solve the inequality 5−2(3x−1)>4x+275 - 2(3x - 1) > 4x + 27, write the solution in interval notation, and describe its number line representation.

Answer

Expand: 5−6x+2>4x+27  ⟹  −6x+7>4x+275 - 6x + 2 > 4x + 27 \implies -6x + 7 > 4x + 27. Collect terms: −10x>20-10x > 20. Divide by −10-10 and reverse the sign: x<−2x < -2. Interval notation: (−∞,−2)(-\infty, -2). Number line: an open circle at −2-2 with a shaded ray extending to the left.

03

Solve the compound inequality −18≤−3(x+2)<9-18 \le -3(x + 2) < 9 for xx, express the result in interval notation, and describe the graph on a number line.

Answer

Divide all parts by −3-3 and reverse the inequality signs: 6≥x+2>−36 \ge x + 2 > -3, which rewrites as −3<x+2≤6-3 < x + 2 \le 6. Subtract 22: −5<x≤4-5 < x \le 4. Interval notation: (−5,4](-5, 4]. Number line: an open circle at −5-5, a solid circle at 44, and the line segment between them shaded.

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