Resources
Solve the linear inequality for , express the solution set in interval notation, and describe the geometric representation of the solution set on a real number line.
Answer and steps
Final answer
Interval notation: ; on the number line, a solid closed circle at with a shaded ray extending indefinitely to the left.
Steps
Expand and simplify both sides
To solve the inequality, write the solution in interval notation, and graph it on a number line, follow these steps:
Apply the distributive property to the left side of the inequality:
Collect variable terms and constant terms
Subtract from both sides to group the -terms on the left:
Subtract from both sides to isolate the variable term:
Divide by the coefficient of
Divide both sides by .
Important Rule: Whenever an inequality is multiplied or divided by a negative number, the direction of the inequality sign must be reversed.
Write in interval notation
The inequality includes all real numbers less than or equal to .
- The lower bound extends indefinitely to the left: (always written with an open parenthesis
(). - The upper bound is , which is included in the solution set (written with a closed bracket
]).
Therefore, the interval notation is:
Describe the graph on a number line
To represent geometrically on a horizontal number line:
- Place a solid (closed) circle at the point to indicate that is included in the solution set.
- Shade a continuous ray pointing to the left from , ending with an arrow pointing toward , representing all values smaller than .
Typical errors
01 The student forgets to reverse the inequality direction when dividing by a negative number, resulting in x ≥ 4.
Sample Student Work
Reviewed by ACEpath TeacherStep-by-Step Review
Walk Through It with Your Teacher- Step 1
-3(2x - 5) 4x - 25 -6x + 15 4x - 25 -10x -40
- Step 2Correct
When dividing or multiplying both sides of an inequality by a negative number (here, ), the inequality sign must flip direction. Dividing by changes to , yielding .
- Step 3
](streamdown:incomplete-link)
CorrectYour interval notation correctly reflects your intermediate result , but because the sign was not reversed in the previous step, the true solution set is .
- Step 4
4
Correct4 -
Your graph accurately matches your written interval , but since the actual solution is , the ray should shade to the left toward .](streamdown:incomplete-link)
WHAT YOU DID WELL
Compliments from Your TeacherYou expanded accurately to get .
You grouped variable terms and constant terms cleanly to isolate .
You correctly used a solid closed circle at to represent an inclusive endpoint.
THE ERROR
Where Your ACEpath Teacher Spotted the Mistakeno
WHY IT HAPPENED
ACEpath Teacher's DiagnosisYou treated division by a negative coefficient just like division in an equation, overlooking the fundamental inequality rule that dividing or multiplying by a negative number reflects values across zero and reverses their relative order.
REASONING PATH
Your ACEpath teacher’s suggested approach- Check the divisor's sign
Whenever you multiply or divide an inequality by a negative quantity, the inequality symbol must immediately flip (e.g., becomes ).
Circle negative coefficients before dividing so you remember to flip the inequality sign in the very next line.
- Test a test point
Any valid solution from your final set must satisfy the original inequality.
Pick an easy test point such as . In the original inequality, is true, so must be in the shaded region. Your graph shaded values greater than , leaving out , which signals an inverted sign.
CORRECTED PATH
ACEpath Teacher's DemonstrationDivide both sides of by and reverse the inequality symbol: .
Write in interval notation: .
Plot on the number line: place a solid closed circle at and shade the ray extending to the left toward .
Interval notation: ; Number line: a solid closed circle at with a shaded ray extending to the left.
02 The student incorrectly distributes the negative sign to the second term inside the parentheses as -15 instead of +15, leading to -10x ≥ -10 and x ≤ 1.
Sample Student Work
Reviewed by ACEpath TeacherStep-by-Step Review
Walk Through It with Your Teacher- Step 1
-3(2x - 5) 4x - 25 -6x - 15 4x - 25
Correct-3(2x - 5) 4x - 25 -6x + 15 4x - 25
When distributing to both terms inside the parentheses, multiplying two negative numbers gives a positive: , not .
- Step 2
-10x -10 x 1
Correct-10x -40 x 4
Your algebraic rearrangement and rule application were correct based on your previous step (including reversing the inequality symbol when dividing by ), but the values were affected by the earlier sign mistake.
- Step 3
(-, 1] 1
Correct(-, 4] 4
Your interval notation and number line representation accurately matched your value of , but the correct endpoint is .
WHAT YOU DID WELL
Compliments from Your TeacherYou correctly remembered to reverse the direction of the inequality sign when dividing both sides by the negative coefficient .
You correctly represented a non-strict inequality () using a closed bracket in interval notation and a solid circle on the number line.
You correctly shaded the number line toward negative infinity to represent values less than the endpoint.
THE ERROR
Where Your ACEpath Teacher Spotted the MistakeMultiplying by yielded instead of .
WHY IT HAPPENED
ACEpath Teacher's DiagnosisOverlooking the interaction between the negative factor outside parentheses and the negative sign on the subtracted term inside parentheses.
REASONING PATH
Your ACEpath teacher’s suggested approach- Distribute Signs Carefully
For any real numbers , , and , .
Always circle or highlight the sign attached to each term inside the parentheses before distributing a negative multiplier.
CORRECTED PATH
ACEpath Teacher's DemonstrationSubtract and from both sides:
Divide by and flip the inequality sign:
Interval notation: ; on the number line, a solid closed circle at with a shaded ray extending to the left.
03 The student confuses non-strict and strict inequalities at the boundary, treating ≥ as > and using an open interval and an open circle at 4.
Sample Student Work
Reviewed by ACEpath TeacherStep-by-Step Review
Walk Through It with Your Teacher- Step 1
- Step 2Correct
When dividing both sides of by , the inequality symbol reverses from to . You correctly flipped the direction, but omitted the 'or equal to' bar, treating a non-strict inequality as a strict one.
- Step 3Correct
Because includes the boundary point , the upper bound requires a square bracket
]rather than a parenthesis). - Step 4
An open circle at with a shaded ray extending to the left.
CorrectA solid (closed) circle at with a shaded ray extending indefinitely to the left.
Because is included in the solution set (), the point at must be plotted as a solid closed circle.
WHAT YOU DID WELL
Compliments from Your TeacherYou expanded accurately using the distributive property.
You collected like terms correctly to reach .
You correctly remembered to reverse the direction of the inequality when dividing by the negative coefficient .
THE ERROR
Where Your ACEpath Teacher Spotted the MistakeYou wrote instead of when dividing both sides by .
WHY IT HAPPENED
ACEpath Teacher's DiagnosisYou focused on reversing the inequality direction upon dividing by a negative number, but lost track of whether the original inequality was strict or non-strict, unintentionally dropping the equality bar.
REASONING PATH
Your ACEpath teacher’s suggested approach- Preserve Equality Status
Dividing or multiplying by a negative number reverses the direction of the inequality, but does not alter whether equality is included: becomes , and becomes .
Always copy the horizontal equality bar along with the flipped inequality sign unless you are intentionally splitting cases.
- Match Symbols to Notation
Non-strict inequalities () always pair with square brackets
[or]and solid closed circles on the number line.Before writing interval notation or drawing a number line, inspect the inequality sign: if it has an equality bar, use a bracket and fill in the circle.
CORRECTED PATH
ACEpath Teacher's DemonstrationDivide both sides by and reverse to : .
Express all values less than or equal to in interval notation: .
Graph the solution by plotting a solid closed circle at and drawing a ray pointing left toward .
Interval notation: ; on the number line, a solid closed circle at with a shaded ray extending indefinitely to the left.
Lock it in
What essential rule must you apply whenever you multiply or divide both sides of an inequality by a negative number?
Reverse the direction of the inequality sign (e.g., becomes , and becomes ).
Similar question
Solve the inequality , express the solution in interval notation, and state the direction of the shaded ray on a number line.
Answer
Subtract : . Divide by and reverse the sign: . Interval notation: . Shaded ray: starts with a solid closed circle at and extends to the right.](streamdown:incomplete-link)
Solve the inequality , write the solution in interval notation, and describe its number line representation.
Answer
Expand: . Collect terms: . Divide by and reverse the sign: . Interval notation: . Number line: an open circle at with a shaded ray extending to the left.
Solve the compound inequality for , express the result in interval notation, and describe the graph on a number line.
Answer
Divide all parts by and reverse the inequality signs: , which rewrites as . Subtract : . Interval notation: . Number line: an open circle at , a solid circle at , and the line segment between them shaded.