Formula For Rotational KeKrot=12Iω2K_{rot} = \frac{1}{2}I\omega^2Krot=21Iω2 Energy of rotation Depends on moment of inertia and angular velocity Analogs of translational KE: 12mv2\frac{1}{2}mv^221mv2 Important for rolling and spinning objects Formula for Rotational KE
Total Kinetic Energy Of Rolling ObjectsKtotal=Ktrans+Krot=12mv2+12Iω2K_{total} = K_{trans} + K_{rot} = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2Ktotal=Ktrans+Krot=21mv2+21Iω2 For rolling without slipping: v=rωv = r\omegav=rω K=12mv2+12(mr2)(vr)2=12mv2(1+Imr2)K = \frac{1}{2}mv^2 + \frac{1}{2}(mr^2)\left(\frac{v}{r}\right)^2 = \frac{1}{2}mv^2\left(1 + \frac{I}{mr^2}\right)K=21mv2+21(mr2)(rv)2=21mv2(1+mr2I) K=12mv2(1+β)K = \frac{1}{2}mv^2\left(1 + \beta\right)K=21mv2(1+β) where β=I/(mr2)\beta = I/(mr^2)β=I/(mr2) Solid sphere: β=2/5\beta = 2/5β=2/5, hollow sphere: β=2/3\beta = 2/3β=2/3, cylinder: β=1/2\beta = 1/2β=1/2 Total Kinetic Energy of Rolling Objects
Races On Inclines Objects with different shapes roll down incline Faster object reaches bottom first (has larger acceleration) Depends on β=I/(mr2)\beta = I/(mr^2)β=I/(mr2) Smaller β\betaβ -> larger acceleration Results independent of mass and radius Races on Inclines
Angular Momentum Of Rigid BodiesL=IωL = I\omegaL=Iω Rotational analog of linear momentum (p=mvp = mvp=mv) Vector quantity: direction along rotation axis Units: kg - m2/s Conserved when τnet=0\tau_{net} = 0τnet=0 Angular Momentum of Rigid Bodies
Angular Momentum Of ParticlesL=mvr⊥L = mvr_\perpL=mvr⊥ (for point particle) Perpendicular distance from reference point to velocity line Depends on choice of reference point Conserved when net external torque = 0 Angular Momentum of Particles
Change In Angular MomentumΔL=τnetΔt\Delta L = \tau_{net}\Delta tΔL=τnetΔt Net torque causes change in angular momentum Analogous to impulse-momentum theorem Important for rotational collisions Change in Angular Momentum
Conditions For Angular Momentum Conservation Net external torque on system = 0 Internal torques cancel (action-reaction pairs) System isolated from external rotational influences Can hold even during collisions Conditions for Angular Momentum Conservation
Changing Moment Of Inertia Example Skater Iiωi=IfωfI_i\omega_i = I_f\omega_fIiωi=Ifωf Skater pulls arms in: III decreases, ω\omegaω increases Angular momentum conserved (no external torque) Used by figure skaters, divers Demonstrates conservation in action Changing Moment of Inertia example Skater
Planetary Orbits Planets sweep out equal areas in equal times (Kepler's 2nd Law) Conservation of angular momentum L=mvr=constantL = mvr = \text{constant}L=mvr=constant (approximately circular orbits) Explains why orbits are stable Planetary Orbits
Formula For Rotational KeKrot=12Iω2K_{rot} = \frac{1}{2}I\omega^2Krot=21Iω2 Energy of rotation Depends on moment of inertia and angular velocity Analogs of translational KE: 12mv2\frac{1}{2}mv^221mv2 Important for rolling and spinning objects Formula for Rotational KE
Total Kinetic Energy Of Rolling ObjectsKtotal=Ktrans+Krot=12mv2+12Iω2K_{total} = K_{trans} + K_{rot} = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2Ktotal=Ktrans+Krot=21mv2+21Iω2 For rolling without slipping: v=rωv = r\omegav=rω K=12mv2+12(mr2)(vr)2=12mv2(1+Imr2)K = \frac{1}{2}mv^2 + \frac{1}{2}(mr^2)\left(\frac{v}{r}\right)^2 = \frac{1}{2}mv^2\left(1 + \frac{I}{mr^2}\right)K=21mv2+21(mr2)(rv)2=21mv2(1+mr2I) K=12mv2(1+β)K = \frac{1}{2}mv^2\left(1 + \beta\right)K=21mv2(1+β) where β=I/(mr2)\beta = I/(mr^2)β=I/(mr2) Solid sphere: β=2/5\beta = 2/5β=2/5, hollow sphere: β=2/3\beta = 2/3β=2/3, cylinder: β=1/2\beta = 1/2β=1/2 Total Kinetic Energy of Rolling Objects
Races On Inclines Objects with different shapes roll down incline Faster object reaches bottom first (has larger acceleration) Depends on β=I/(mr2)\beta = I/(mr^2)β=I/(mr2) Smaller β\betaβ -> larger acceleration Results independent of mass and radius Races on Inclines
Angular Momentum Of Rigid BodiesL=IωL = I\omegaL=Iω Rotational analog of linear momentum (p=mvp = mvp=mv) Vector quantity: direction along rotation axis Units: kg - m2/s Conserved when τnet=0\tau_{net} = 0τnet=0 Angular Momentum of Rigid Bodies
Angular Momentum Of ParticlesL=mvr⊥L = mvr_\perpL=mvr⊥ (for point particle) Perpendicular distance from reference point to velocity line Depends on choice of reference point Conserved when net external torque = 0 Angular Momentum of Particles
Change In Angular MomentumΔL=τnetΔt\Delta L = \tau_{net}\Delta tΔL=τnetΔt Net torque causes change in angular momentum Analogous to impulse-momentum theorem Important for rotational collisions Change in Angular Momentum
Conditions For Angular Momentum Conservation Net external torque on system = 0 Internal torques cancel (action-reaction pairs) System isolated from external rotational influences Can hold even during collisions Conditions for Angular Momentum Conservation
Changing Moment Of Inertia Example Skater Iiωi=IfωfI_i\omega_i = I_f\omega_fIiωi=Ifωf Skater pulls arms in: III decreases, ω\omegaω increases Angular momentum conserved (no external torque) Used by figure skaters, divers Demonstrates conservation in action Changing Moment of Inertia example Skater
Planetary Orbits Planets sweep out equal areas in equal times (Kepler's 2nd Law) Conservation of angular momentum L=mvr=constantL = mvr = \text{constant}L=mvr=constant (approximately circular orbits) Explains why orbits are stable Planetary Orbits