ACEpath
Select Subject
Select Unit

Angular Displacement Velocity Acceleration

  • Angular displacement (θ\theta): Radian measure of rotation angle
  • Angular velocity (ω\omega): ω=dθdt\omega = \frac{d\theta}{dt} (rad/s)
  • Angular acceleration (α\alpha): α=dωdt=d2θdt2\alpha = \frac{d\omega}{dt} = \frac{d^2\theta}{dt^2} (rad/s2))))

Rotational Kinematics Equations

ω=ω0+αt\omega = \omega_0 + \alpha t θ=θ0+ω0t+12αt2\theta = \theta_0 + \omega_0 t + \frac{1}{2}\alpha t^2 ω2=ω02+2αΔθ\omega^2 = \omega_0^2 + 2\alpha\Delta\theta

  • Analogs of linear kinematic equations
  • Apply separately from linear motion

Relationship v=rωv=r\omega And a=rαa=r\alpha

  • v=rωv = r\omega (rolling without slipping condition)
  • a=rαa = r\alpha (rolling without slipping)
  • x=rθx = r\theta, v=rωv = r\omega, a=rαa = r\alpha
  • Connects linear and angular quantities
  • Essential for rolling problems

Rolling Without Slipping Condition

  • Point of contact is instantaneously at rest relative to surface
  • vcm=Rωv_{cm} = R\omega (no slipping)
  • acm=Rαa_{cm} = R\alpha
  • Friction provides necessary force (static friction)
  • fsμsNf_s \leq \mu_s N must hold for no slip

Definition Of Torque

τ=rFsinθ=Fd\tau = rF\sin\theta = F_\perp d

  • Rotational analog of force
  • Causes angular acceleration
  • Units: N - m
  • Depends on force magnitude, distance from axis, angle

Lever Arm

  • Perpendicular distance from axis to line of action of force
  • d=rsinθd_\perp = r\sin\theta
  • Maximizes torque when force applied perpendicular to lever arm
  • Longer lever arm = more torque for same force

Maximizing Torque

  • For given force, maximize distance from axis (perpendicular)
  • Apply force perpendicular to lever arm
  • τmax=rF\tau_{max} = rF (when θ=90degrees\theta = 90 degrees )
  • τ=rFsinθ\tau = rF\sin\theta

Definition Of Moment Of Inertia

I=miri2I = \sum m_i r_i^2

  • Rotational analog of mass
  • Measure of resistance to angular acceleration
  • Depends on mass distribution and axis of rotation
  • Units: kg - m2
  • Point mass: I=mr2I = mr^2

Mass Distribution Effect

  • Mass farther from axis increases I more
  • Hollow objects have larger I than solid objects of same mass
  • Shape matters: ring > disk > solid sphere (same mass, different I)
  • Can modify rotational inertia by redistributing mass

Parallel Axis Theorem Concept

Parallel Axis Theorem:

Moment of inertia about any axis.

I=Icm+Md2I = I_{cm} + Md^2

Where:

  • IcmI_{cm} = moment about center of mass
  • M = total mass
  • d = distance between axes

Common shapes (about center of mass):

  • Point mass: mr2mr^2
  • Thin rod (length L, ⟂): 112mL2\frac{1}{12}mL^2
  • Solid cylinder/disk (radius R): 12mR2\frac{1}{2}mR^2
  • Thin cylindrical shell: mR2mR^2
  • Solid sphere (radius R): 25mR2\frac{2}{5}mR^2
  • Thin spherical shell: 23mR2\frac{2}{3}mR^2

Conditions For Rotational Equilibrium

  • Translational equilibrium: F=0\sum \vec{F} = 0
  • Rotational equilibrium: τ=0\sum \tau = 0 about any axis
  • Both conditions required for static equilibrium
  • No net force, no net torque

Selecting A Pivot Point

  • Can place pivot at any convenient location
  • Unknown forces at pivot eliminated from torque equation
  • Strategic choice simplifies problem-solving
  • Always check translational equilibrium too

Net Torque Equals II Times α\alpha

τnet=Iα\tau_{net} = I\alpha

  • Rotational analog of F=maF = ma
  • Causes angular acceleration
  • Sum of all torques about axis
  • Applies to rigid bodies

Rigid Body Dynamics

  • Combination of translation and rotation
  • Fnet=MacmF_{net} = Ma_{cm} (translational)
  • τnet=Icmα\tau_{net} = I_{cm}\alpha (rotational about center of mass)
  • Need to solve both simultaneously
  • Examples: rolling objects, swinging objects