System Vs Object Object: Single rigid body System: Collection of objects that can move together or separately Can treat system as single object located at center of mass Internal forces cancel out (Newton's 3rd Law)) System vs Object
Calculating Center Of Mass xcm=m1x1+m2x2+...m1+m2+...x_{cm} = \frac{m_1x_1 + m_2x_2 + ...}{m_1 + m_2 + ...}xcm=m1+m2+...m1x1+m2x2+... ycm=m1y1+m2y2+...m1+m2+...y_{cm} = \frac{m_1y_1 + m_2y_2 + ...}{m_1 + m_2 + ...}ycm=m1+m2+...m1y1+m2y2+... For continuous objects: xcm=1M∫x dmx_{cm} = \frac{1}{M}\int x\,dmxcm=M1∫xdm System behaves as if all mass concentrated at center of mass Calculating Center of Mass
Motion Of The Center Of Mass Fnet,ext=MacmF_{net,ext} = Ma_{cm}Fnet,ext=Macm (Newton's 2nd Law for systems) Center of mass moves as if all external force applied there Internal forces don't affect center of mass motion Crucial for connected objects problems Motion of the Center of Mass
Contact Forces Vs Field Forces Contact forces: Require physical contact Normal force, tension, friction, spring force Field forces: Act at a distance Gravitational force, electric force, magnetic force Both types included in free-body diagrams Contact Forces vs Field Forces
Drawing Free-body Diagrams / Fbd Isolate the object of interest Identify all forces acting ON the object (not BY the object) Draw arrows from center of mass in direction of force Label forces with standard notation Choose coordinate system Include magnitudes if known or use variables Drawing Free-Body Diagrams / FBD
Tension And Normal Force Normal force (NNN): Perpendicular to contact surface Prevents interpenetration of objects Self-adjusting: magnitude adjusts as needed Not equal to weight (common misconception) Tension (TTT): Pulling force along rope/string Transmits force through rope Constant throughout ideal rope (massless) Direction along rope away from object Tension and Normal Force
Action-reaction Pairs For every action, there is an equal and opposite reaction Forces act on different objects (never on same object) Equal in magnitude, opposite in direction Same type of force (force on A by B, force on B by A) Example: Earth pulls you down, you pull Earth up (equal and opposite) Action-Reaction Pairs
Interaction Between Objects Forces always occur in pairs Each force in pair has different object experiencing it Cannot cancel each other (act on different objects) Essential for analyzing connected objects and collisions Interaction between Objects
Inertia And Mass Inertia: Resistance to change in motion Proportional to mass Quantified by Newton's First Law Mass: measure of inertia (scalar) Greater mass = greater inertia Inertia and Mass
Conditions For Equilibrium Translational equilibrium: ∑F⃗=0\sum \vec{F} = 0∑F=0 Vector sum of all forces = zero No net force on object Velocity constant (could be zero or non-zero) Conditions for Equilibrium
Static Vs Dynamic Equilibrium Static equilibrium: Object at rest (v=0v = 0v=0) Dynamic equilibrium: Object moving with constant velocity Both satisfy ∑F⃗=0\sum \vec{F} = 0∑F=0 Both are equilibrium states Static vs Dynamic Equilibrium
F=maF=maF=ma ApplicationF⃗net=ma⃗\vec{F}_{net} = m\vec{a}Fnet=ma Net force causes acceleration Acceleration is directly proportional to net force Acceleration is inversely proportional to mass Vector equation (direction matters) Component form: Fx=maxF_x = ma_xFx=max, Fy=mayF_y = ma_yFy=may $F=ma$ Application
Forces On Inclined Planes Weight components: Parallel to incline: mgsinθmg\sin\thetamgsinθ Perpendicular to incline: mgcosθmg\cos\thetamgcosθ Normal force: N=mgcosθN = mg\cos\thetaN=mgcosθ (flat incline) Friction acts parallel to surface (opposes motion) Acceleration down incline: a=gsinθ−μkgcosθa = g\sin\theta - \mu_k g\cos\thetaa=gsinθ−μkgcosθ Forces on Inclined Planes
Atwood Machines / Connected Objects Two masses connected by string over pulley Same tension throughout string Acceleration: a=(m1−m2)gm1+m2a = \frac{(m_1 - m_2)g}{m_1 + m_2}a=m1+m2(m1−m2)g Tension: T=2m1m2gm1+m2T = \frac{2m_1m_2g}{m_1 + m_2}T=m1+m22m1m2g Heavier mass accelerates downward, lighter upward Atwood Machines / Connected Objects
Apparent Weight Normal force perceived by person in accelerating reference frame Elevator accelerating upward: Napparent=m(g+a)N_{apparent} = m(g + a)Napparent=m(g+a) Elevator accelerating downward: Napparent=m(g−a)N_{apparent} = m(g - a)Napparent=m(g−a) Zero apparent weight during free fall Apparent Weight
Law Of Universal GravitationFg=Gm1m2r2F_g = G\frac{m_1 m_2}{r^2}Fg=Gr2m1m2 G=6.67×10−11G = 6.67 \times 10^{-11}G=6.67×10−11 N - m2/kg2 Inverse square law Attractive force between any two masses Explains planetary motion Law of Universal Gravitation
Gravitational Field Strength 'G' g=Fgm=GMr2g = \frac{F_g}{m} = \frac{GM}{r^2}g=mFg=r2GM Gravitational acceleration near Earth's surface: g=9.8g = 9.8g=9.8 m/s2 Varies with altitude and planet Independent of falling object's mass Gravitational Field Strength 'g'
Inertial Mass Vs Gravitational Mass Inertial mass: Resistance to acceleration (m=F/am = F/am=F/a) Gravitational mass: Strength of gravitational attraction Experimentally found to be equivalent (Equivalence Principle) All objects fall with same acceleration in vacuum Inertial Mass vs Gravitational Mass
Static Friction And Maximum Limit fs≤μsNf_s \leq \mu_s Nfs≤μsN Static friction prevents relative motion Can range from zero to maximum value Adjusts to match applied force (until limit reached) μs\mu_sμs: coefficient of static friction Static Friction and Maximum Limit
Kinetic Friction Formula fk=μkNf_k = \mu_k Nfk=μkN Kinetic friction opposes sliding motion Constant magnitude while sliding μk\mu_kμk: coefficient of kinetic friction Always μk<μs\mu_k < \mu_sμk<μs Kinetic Friction Formula
Coefficient Of Friction Dimensionless quantity (0 to 1, typically) Depends on materials in contact μs\mu_sμs: static coefficient μk\mu_kμk: kinetic coefficient Ice on ice: μ≈0.1\mu \approx 0.1μ≈0.1, rubber on concrete: μ≈1.0\mu \approx 1.0μ≈1.0 Coefficient of Friction
Hooke's LawFspring=−kxF_{spring} = -kxFspring=−kx Restoring force proportional to displacement Direction opposite to displacement kkk: spring constant (N/m) xxx: displacement from equilibrium Valid for elastic deformation (within elastic limit) Negative sign indicates restoring force Hooke's Law
Ideal Spring Model Massless spring (no inertia) Hooke's law perfectly obeyed No damping Restoring force only depends on displacement Simplifies calculations Ideal Spring Model
Centripetal Force Concept Net force directed toward center of circular path Causes change in direction of velocity Not a new force, but name for net force Examples: tension, gravity, normal force, friction Fc=mv2r=macF_c = \frac{mv^2}{r} = ma_cFc=rmv2=mac Centripetal Force Concept
Centripetal Acceleration ac=v2r=ω2ra_c = \frac{v^2}{r} = \omega^2rac=rv2=ω2r Directed toward center of circle Perpendicular to velocity Constant magnitude for uniform circular motion Required for circular motion Centripetal Acceleration
Banking Curves No friction needed for correct speed tanθ=v2rg\tan\theta = \frac{v^2}{rg}tanθ=rgv2 Design speed for given bank angle At design speed: Nsinθ=mv2/rN\sin\theta = mv^2/rNsinθ=mv2/r (provides centripetal force) Different speeds require friction Banking Curves
Vertical Circular Motion Top of loop: minimum speed vmin=gRv_{min} = \sqrt{gR}vmin=gR Tension + weight provides centripetal force At minimum speed: tension = 0, weight alone sufficient Bottom of loop: maximum tension Tension - weight provides centripetal force T=m(g+v2r)T = m\left(g + \frac{v^2}{r}\right)T=m(g+rv2) Vertical Circular Motion
System Vs Object Object: Single rigid body System: Collection of objects that can move together or separately Can treat system as single object located at center of mass Internal forces cancel out (Newton's 3rd Law)) System vs Object
Calculating Center Of Mass xcm=m1x1+m2x2+...m1+m2+...x_{cm} = \frac{m_1x_1 + m_2x_2 + ...}{m_1 + m_2 + ...}xcm=m1+m2+...m1x1+m2x2+... ycm=m1y1+m2y2+...m1+m2+...y_{cm} = \frac{m_1y_1 + m_2y_2 + ...}{m_1 + m_2 + ...}ycm=m1+m2+...m1y1+m2y2+... For continuous objects: xcm=1M∫x dmx_{cm} = \frac{1}{M}\int x\,dmxcm=M1∫xdm System behaves as if all mass concentrated at center of mass Calculating Center of Mass
Motion Of The Center Of Mass Fnet,ext=MacmF_{net,ext} = Ma_{cm}Fnet,ext=Macm (Newton's 2nd Law for systems) Center of mass moves as if all external force applied there Internal forces don't affect center of mass motion Crucial for connected objects problems Motion of the Center of Mass
Contact Forces Vs Field Forces Contact forces: Require physical contact Normal force, tension, friction, spring force Field forces: Act at a distance Gravitational force, electric force, magnetic force Both types included in free-body diagrams Contact Forces vs Field Forces
Drawing Free-body Diagrams / Fbd Isolate the object of interest Identify all forces acting ON the object (not BY the object) Draw arrows from center of mass in direction of force Label forces with standard notation Choose coordinate system Include magnitudes if known or use variables Drawing Free-Body Diagrams / FBD
Tension And Normal Force Normal force (NNN): Perpendicular to contact surface Prevents interpenetration of objects Self-adjusting: magnitude adjusts as needed Not equal to weight (common misconception) Tension (TTT): Pulling force along rope/string Transmits force through rope Constant throughout ideal rope (massless) Direction along rope away from object Tension and Normal Force
Action-reaction Pairs For every action, there is an equal and opposite reaction Forces act on different objects (never on same object) Equal in magnitude, opposite in direction Same type of force (force on A by B, force on B by A) Example: Earth pulls you down, you pull Earth up (equal and opposite) Action-Reaction Pairs
Interaction Between Objects Forces always occur in pairs Each force in pair has different object experiencing it Cannot cancel each other (act on different objects) Essential for analyzing connected objects and collisions Interaction between Objects
Inertia And Mass Inertia: Resistance to change in motion Proportional to mass Quantified by Newton's First Law Mass: measure of inertia (scalar) Greater mass = greater inertia Inertia and Mass
Conditions For Equilibrium Translational equilibrium: ∑F⃗=0\sum \vec{F} = 0∑F=0 Vector sum of all forces = zero No net force on object Velocity constant (could be zero or non-zero) Conditions for Equilibrium
Static Vs Dynamic Equilibrium Static equilibrium: Object at rest (v=0v = 0v=0) Dynamic equilibrium: Object moving with constant velocity Both satisfy ∑F⃗=0\sum \vec{F} = 0∑F=0 Both are equilibrium states Static vs Dynamic Equilibrium
F=maF=maF=ma ApplicationF⃗net=ma⃗\vec{F}_{net} = m\vec{a}Fnet=ma Net force causes acceleration Acceleration is directly proportional to net force Acceleration is inversely proportional to mass Vector equation (direction matters) Component form: Fx=maxF_x = ma_xFx=max, Fy=mayF_y = ma_yFy=may $F=ma$ Application
Forces On Inclined Planes Weight components: Parallel to incline: mgsinθmg\sin\thetamgsinθ Perpendicular to incline: mgcosθmg\cos\thetamgcosθ Normal force: N=mgcosθN = mg\cos\thetaN=mgcosθ (flat incline) Friction acts parallel to surface (opposes motion) Acceleration down incline: a=gsinθ−μkgcosθa = g\sin\theta - \mu_k g\cos\thetaa=gsinθ−μkgcosθ Forces on Inclined Planes
Atwood Machines / Connected Objects Two masses connected by string over pulley Same tension throughout string Acceleration: a=(m1−m2)gm1+m2a = \frac{(m_1 - m_2)g}{m_1 + m_2}a=m1+m2(m1−m2)g Tension: T=2m1m2gm1+m2T = \frac{2m_1m_2g}{m_1 + m_2}T=m1+m22m1m2g Heavier mass accelerates downward, lighter upward Atwood Machines / Connected Objects
Apparent Weight Normal force perceived by person in accelerating reference frame Elevator accelerating upward: Napparent=m(g+a)N_{apparent} = m(g + a)Napparent=m(g+a) Elevator accelerating downward: Napparent=m(g−a)N_{apparent} = m(g - a)Napparent=m(g−a) Zero apparent weight during free fall Apparent Weight
Law Of Universal GravitationFg=Gm1m2r2F_g = G\frac{m_1 m_2}{r^2}Fg=Gr2m1m2 G=6.67×10−11G = 6.67 \times 10^{-11}G=6.67×10−11 N - m2/kg2 Inverse square law Attractive force between any two masses Explains planetary motion Law of Universal Gravitation
Gravitational Field Strength 'G' g=Fgm=GMr2g = \frac{F_g}{m} = \frac{GM}{r^2}g=mFg=r2GM Gravitational acceleration near Earth's surface: g=9.8g = 9.8g=9.8 m/s2 Varies with altitude and planet Independent of falling object's mass Gravitational Field Strength 'g'
Inertial Mass Vs Gravitational Mass Inertial mass: Resistance to acceleration (m=F/am = F/am=F/a) Gravitational mass: Strength of gravitational attraction Experimentally found to be equivalent (Equivalence Principle) All objects fall with same acceleration in vacuum Inertial Mass vs Gravitational Mass
Static Friction And Maximum Limit fs≤μsNf_s \leq \mu_s Nfs≤μsN Static friction prevents relative motion Can range from zero to maximum value Adjusts to match applied force (until limit reached) μs\mu_sμs: coefficient of static friction Static Friction and Maximum Limit
Kinetic Friction Formula fk=μkNf_k = \mu_k Nfk=μkN Kinetic friction opposes sliding motion Constant magnitude while sliding μk\mu_kμk: coefficient of kinetic friction Always μk<μs\mu_k < \mu_sμk<μs Kinetic Friction Formula
Coefficient Of Friction Dimensionless quantity (0 to 1, typically) Depends on materials in contact μs\mu_sμs: static coefficient μk\mu_kμk: kinetic coefficient Ice on ice: μ≈0.1\mu \approx 0.1μ≈0.1, rubber on concrete: μ≈1.0\mu \approx 1.0μ≈1.0 Coefficient of Friction
Hooke's LawFspring=−kxF_{spring} = -kxFspring=−kx Restoring force proportional to displacement Direction opposite to displacement kkk: spring constant (N/m) xxx: displacement from equilibrium Valid for elastic deformation (within elastic limit) Negative sign indicates restoring force Hooke's Law
Ideal Spring Model Massless spring (no inertia) Hooke's law perfectly obeyed No damping Restoring force only depends on displacement Simplifies calculations Ideal Spring Model
Centripetal Force Concept Net force directed toward center of circular path Causes change in direction of velocity Not a new force, but name for net force Examples: tension, gravity, normal force, friction Fc=mv2r=macF_c = \frac{mv^2}{r} = ma_cFc=rmv2=mac Centripetal Force Concept
Centripetal Acceleration ac=v2r=ω2ra_c = \frac{v^2}{r} = \omega^2rac=rv2=ω2r Directed toward center of circle Perpendicular to velocity Constant magnitude for uniform circular motion Required for circular motion Centripetal Acceleration
Banking Curves No friction needed for correct speed tanθ=v2rg\tan\theta = \frac{v^2}{rg}tanθ=rgv2 Design speed for given bank angle At design speed: Nsinθ=mv2/rN\sin\theta = mv^2/rNsinθ=mv2/r (provides centripetal force) Different speeds require friction Banking Curves
Vertical Circular Motion Top of loop: minimum speed vmin=gRv_{min} = \sqrt{gR}vmin=gR Tension + weight provides centripetal force At minimum speed: tension = 0, weight alone sufficient Bottom of loop: maximum tension Tension - weight provides centripetal force T=m(g+v2r)T = m\left(g + \frac{v^2}{r}\right)T=m(g+rv2) Vertical Circular Motion