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dydx=dydtdxdt\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}

dy/dx = (dy/dt)/(dx/dt)

dydx=dy/dtdx/dt=g(t)f(t)\frac{dy}{dx} = \frac{dy/dt}{dx/dt} = \frac{g'(t)}{f'(t)}

Arc Length = ab(dxdt)2+(dydt)2dt\int_{a}^{b} \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2} dt

Arc Length = ∫ab(dx/dt)2+(dy/dt)2dt\int_a^b \sqrt{(dx/dt)^2 + (dy/dt)^2} dt∫ab​(dx/dt)2+(dy/dt)2​dt

L=ab(f(t))2+(g(t))2dtL = \int_a^b \sqrt{(f'(t))^2 + (g'(t))^2}\,dt

Integral Of r(t)=x(t)dt,y(t)dt\mathbf{r}(t) = \langle \int x(t)dt, \int y(t)dt \rangle

Integral of r(t) = <∫x(t)dt,∫y(t)dt\int x(t)dt, \int y(t)dt∫x(t)dt,∫y(t)dt>

r(t)dt=x(t)dt,y(t)dt\int \vec{r}(t)dt = \langle \int x(t)dt, \int y(t)dt \rangle

Position, Velocity, Acceleration Vectors

  • v(t)=r(t)\vec{v}(t) = \vec{r}'(t)
  • a(t)=r(t)\vec{a}(t) = \vec{r}''(t)
  • Speed = v(t)|\vec{v}(t)|

Polar Coordinates (r,θ)(r, \theta)

Polar Coordinates (r, θ)

x=rcosθ,y=rsinθx = r\cos\theta, \quad y = r\sin\theta

Dy/dx In Polar Form

dydx=rsinθ+rcosθrcosθrsinθ\frac{dy}{dx} = \frac{r'\sin\theta + r\cos\theta}{r'\cos\theta - r\sin\theta}

where r=drdθr' = \frac{dr}{d\theta}

Area = 12αβ[r(θ)]2dθ\frac{1}{2} \int_{\alpha}^{\beta} [r(\theta)]^2 d\theta

Area = (1/2) ∫αβ[r(θ)]2dθ\int_\alpha^\beta [r(\theta)]^2 d\theta∫αβ​[r(θ)]2dθ

A=12αβ[r(θ)]2dθA = \frac{1}{2}\int_\alpha^\beta [r(\theta)]^2 d\theta

Area = 12αβ([R(θ)]2[r(θ)]2)dθ\frac{1}{2} \int_{\alpha}^{\beta} ([R(\theta)]^2 - [r(\theta)]^2) d\theta

Area = (1/2) ∫αβ([R(θ)]2−[r(θ)]2)dθ\int_\alpha^\beta ([R(\theta)]^2 - [r(\theta)]^2) d\theta∫αβ​([R(θ)]2−[r(θ)]2)dθ

A=12αβ([R(θ)]2[r(θ)]2)dθA = \frac{1}{2}\int_\alpha^\beta ([R(\theta)]^2 - [r(\theta)]^2)d\theta

where R(θ) ≥ r(θ) on [alpha, β].

Arc Length = αβ[r(θ)]2+(drdθ)2dθ\int_{\alpha}^{\beta} \sqrt{[r(\theta)]^2 + (\frac{dr}{d\theta})^2} d\theta

Arc Length = ∫αβr(θ)2+(dr/dθ)2dθ\int_\alpha^\beta \sqrt{r(\theta)^2 + (dr/d\theta)^2} d\theta∫αβ​r(θ)2+(dr/dθ)2​dθ

L=αβr2+(drdθ)2dθL = \int_\alpha^\beta \sqrt{r^2 + \left(\frac{dr}{d\theta}\right)^2}\,d\theta